ExamBro
ExamBro
AP EAMCET · Chemistry · Chemical Kinetics

The rate equation for the reaction \(2 A+B \longrightarrow\) products is rate \(=k[A][B]^2\).
If \(k\) at \(T(\mathrm{~K})\) is \(5.0 \times 10^{-6} \mathrm{~mol}^{-2} \mathrm{~L}^2 \mathrm{~s}^{-1}\), the initial rate of the reaction, when \([A]=0.05 \mathrm{~mol} \mathrm{~L}^{-1}\) and \([B]=0.1 \mathrm{~mol} \mathrm{~L}^{-1}\) is

  1. A \(1.25 \times 10^{-9} \mathrm{~L} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}\)
  2. B \(1.25 \times 10^{-9} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}\)
  3. C \(2.50 \times 10^{-9} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}\)
  4. D \(2.50 \times 10^{-9} \mathrm{~L} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(2.50 \times 10^{-9} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}\)

Step-by-step Solution

Detailed explanation

For the reaction, \(2 A+B \longrightarrow\) Products \(\text {Rate }=k[A][B]^2\) Given, Rate constant, \(k\) of reaction \(=5.0 \times 10^{-6} \mathrm{~mol}^{-2} \mathrm{~L}^2 \mathrm{~s}^{-1}\)…