AP EAMCET · Chemistry · Classification of Elements and Periodicity in Properties
The outer electronic configuration of " \(\mathrm{Pd}\) " is
- A \(4 d^8 5 s^2\)
- B \(4 d^9 5 s^1\)
- C \(4 d^{10} 5 s^0\)
- D \(4 d^{10} 5 s^1\)
Answer & Solution
Correct Answer
(C) \(4 d^{10} 5 s^0\)
Step-by-step Solution
Detailed explanation
The atomic number of polladium is 46 . Hence, its electronic configuration of palladium (Pd) is \([\mathrm{Kr}] 4 d^{10}, 5 s^0\) So, its outer electronic configuration is \(4 d^{10} 5 s^0\).
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