AP EAMCET · Chemistry · Some Basic Concepts of Chemistry
The number of moles of solute present in the solutions of I, II and III is respectively
I. \(500 \mathrm{~mL}\) of \(0.2 \mathrm{M} \mathrm{NaOH}\)
II. \(200 \mathrm{~mL}\) of \(0.1 \mathrm{~N} \mathrm{H}_2 \mathrm{SO}_4\)
III. \(6 \mathrm{~g}\) of urea in \(1 \mathrm{~kg}\) of water
- A \(0.1,0.01,0.1\)
- B \(0.1,0.02,0.1\)
- C \(0.2,0.01,0.1\)
- D \(0.1,0.01,0.2\)
Answer & Solution
Correct Answer
(A) \(0.1,0.01,0.1\)
Step-by-step Solution
Detailed explanation
I. Moles of solute \(\mathrm{NaOH}=\) molarity \(=\frac{0.2 \times 500}{1000}=0.1 \mathrm{~mol}\) II. Normality \(=n\)-factor \(\times\) molarity…
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