AP EAMCET · Chemistry · Chemical Bonding and Molecular Structure
The correct order of energy of \(\sigma_{2 p}, \pi_{2 p}, \pi_{2 p}^*\) and \(\sigma_{2 p}^*\) orbitals in \(F_2\) is
- A \(\sigma_{2 \mathrm{p}}>\pi_{2 \mathrm{p}}>\pi_{2 \mathrm{p}}^*>\sigma_{2 \mathrm{p}}^*\)
- B \(\sigma_{2 \mathrm{p}} < \pi_{2 \mathrm{p}} < \pi_{2 \mathrm{p}}^* < \sigma_{2 \mathrm{p}}^*\)
- C \(\pi_{2 \mathrm{p}}>\sigma_{2 \mathrm{p}}>\pi_{2 \mathrm{p}}^*>\sigma_{2 \mathrm{p}}^*\)
- D \(\pi_{2 p} < \sigma_{2 p} < \pi_{2 p}^* < \sigma_{2 p}^*\)
Answer & Solution
Correct Answer
(B) \(\sigma_{2 \mathrm{p}} < \pi_{2 \mathrm{p}} < \pi_{2 \mathrm{p}}^* < \sigma_{2 \mathrm{p}}^*\)
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