AP EAMCET · Chemistry · Hydrocarbons
Propyne reacts with \(\mathrm{HBr}\) to form Ethe compound \(\mathrm{Z}\) is
- A \(\mathrm{CH}_2(\mathrm{Br}) \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{Br}\)
- B \(\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CHBr}_2\)
- C \(\mathrm{CH}_3 \mathrm{CH}(\mathrm{Br}) \mathrm{CH}_2 \mathrm{Br}\)
- D \(\mathrm{CH}_3 \mathrm{CBr}_2 \mathrm{CH}_3\)
Answer & Solution
Correct Answer
(D) \(\mathrm{CH}_3 \mathrm{CBr}_2 \mathrm{CH}_3\)
Step-by-step Solution
Detailed explanation
This is the electrophilic addition so the product will be 2,2 - dibromo propane.
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