AP EAMCET · Chemistry · Chemical Equilibrium
\(K_p\) for the conversion of oxygen to ozone at \(400 \mathrm{~K}\) is \(1.0 \times 10^{-30}\), its standard Gibbs energy change in \(\mathrm{kJ} \mathrm{mol}^{-1}\) is approximately
- A 229.8
- B 114.9
- C -229.8
- D -114.9
Answer & Solution
Correct Answer
(A) 229.8
Step-by-step Solution
Detailed explanation
Given, \(K_p\) for the conversion of oxygen to ozone at \(400 \mathrm{~K}\) is \(1.0 \times 10^{-30}\). \(\left(\Delta G^{\circ}\right)\) standard Gibbs energy change \(=\) ? \(\Delta G^{\circ}=-R T \ln K_p=2.303 R T \log _{10} K_p\) Here, \(R=8.314 \mathrm{~J} / \mathrm{mol}\)…
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