AP EAMCET · Chemistry · States of Matter
If two molecules of \(A\) and \(B\) having mass \(100 \mathrm{~kg}\) and \(64 \mathrm{~kg}\) and rate of diffusion of \(A\) is \(12 \times 10^{-3}\), then rate of diffusion of \(B\) will be
- A \(15 \times 10^{-3}\)
- B \(64 \times 10^{-3}\)
- C \(36 \times 10^{-3}\)
- D \(10 \times 10^{-3}\)
Answer & Solution
Correct Answer
(A) \(15 \times 10^{-3}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & m_A=\left(\frac{100}{2}\right) \mathrm{kg} / \text { molecule } \\ & m_B=\left(\frac{64}{2}\right) \mathrm{kg} / \text { molecule }\end{aligned}\) Rate of diffusion, \(r_B=\) ? \(r_A=12 \times 10^{-3}\) According to Graham's law of diffusion,…
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