AP EAMCET · Chemistry · Ionic Equilibrium
If the molar solubility (in \(\mathrm{mol} \mathrm{L}^{-1}\) ) of a sparingly soluble salt \(A B_4\) is \(S\) and the corresponding solubility product is \(K_{\text {sp }}\), then \(s\) in terms of \(K_{\mathrm{sp}}\) is given by the relation
- A \(S=\left(\frac{K_{\mathrm{sp}}}{128}\right)^{1 / 4}\)
- B \(S=\left(\frac{K_{\mathrm{sp}}}{256}\right)^{1 / 5}\)
- C \(S=\left(256 K_{\mathrm{sp}}\right)^{1 / 5}\)
- D \(S=\left(128 K_{\mathrm{sp}}\right)^{1 / 4}\)
Answer & Solution
Correct Answer
(B) \(S=\left(\frac{K_{\mathrm{sp}}}{256}\right)^{1 / 5}\)
Step-by-step Solution
Detailed explanation
For the reaction, \(\begin{array}{ccc}A B_4(s) \stackrel{(a q)}{\rightleftharpoons} & A^{4+}(a q)+4 B^{-}(a q) \\ - & S & 4 S\end{array}\) Molar solubility (in \(\mathrm{mol} / \mathrm{L}\) ) of a sparingly soluble salt \(A B_4\) is ' \(S\) ' and corresponding solubility product…
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