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AP EAMCET · Chemistry · Redox Reactions

Equivalent weights of \(\mathrm{KMnO}_4\) and \(\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7\) in acidic medium are respectively.
(Molecular weight of \(\mathrm{KMnO}_4=M_A\) and Molecular weight of \(\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7=M_B\) ).

  1. A \(\frac{M_A}{3} \cdot \frac{M_B}{6}\)
  2. B \(\frac{M_A}{6} \cdot \frac{M_B}{5}\)
  3. C \(\frac{M_A}{3} \cdot \frac{M_B}{5}\)
  4. D \(\frac{M_A}{5} \cdot \frac{M_B}{6}\)
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Answer & Solution

Correct Answer

(D) \(\frac{M_A}{5} \cdot \frac{M_B}{6}\)

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Detailed explanation

Given that, Molecular weight of \(\mathrm{KMnO}_4=M_A\) \(\mathrm{MnO}_4^{-}+8 \mathrm{H}^{+}+5 \mathrm{e}^{-} \longrightarrow \mathrm{Mn}^{2+}+4 \mathrm{H}_2 \mathrm{O}\) \(\therefore\) Equivalent weight of \(\mathrm{KMnO}_4\)…
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