AP EAMCET · Chemistry · Electrochemistry
Consider the following cell reaction
\(2 \mathrm{Fe}^{3+}(\mathrm{aq})+2 \mathrm{I}^{-}(\mathrm{aq}) \rightleftharpoons 2 \mathrm{Fe}^{2+}(\mathrm{aq})+\mathrm{I}_2(\mathrm{~s})\)
At 298 K, the cell emf is 0.237 V. The equilibrium constant for the reaction is \(10^x\). The value of \(x\) is
\(\left(\mathrm{F}=96500 \mathrm{C} \mathrm{~mol}^{-1} ; \mathrm{R}=8.3 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}\right)\)
- A \(8\)
- B \(7\)
- C \(6\)
- D \(9\)
Answer & Solution
Correct Answer
(A) \(8\)
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