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AP EAMCET · Chemistry · Structure of Atom

Calculate the mass of an elementary particle, which is accelerated to twice the velocity of light with the precision \(\pm 1 \%\) and has \(1.05 \times 10^{-13} \mathrm{~m}\) uncertainty in position. \(\left(h=6.6 \times 10^{-34} \mathrm{~kg} \mathrm{~m}^2 \mathrm{~s}^{-1}\right)\)

  1. A \(8.34 \times 10^{-27} \mathrm{~kg}\)
  2. B \(0.0083 \mathrm{~kg}\)
  3. C \(0.83 \times 10^{-27} \mathrm{~kg}\)
  4. D \(0.8 \times 10^{-28} \mathrm{~kg}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(0.8 \times 10^{-28} \mathrm{~kg}\)

Step-by-step Solution

Detailed explanation

Precision \(= \pm 1 \%\) \(\therefore\) Accuracy \(=0.01\) \(\begin{aligned} & \Delta v=3 \times 10^8 \times \frac{2}{100}=6 \times 10^6 \mathrm{~m} / \mathrm{s} \\ & \Delta x=1.05 \times 10^{-13} \mathrm{~m}\end{aligned}\) We know that,…