AP EAMCET · Chemistry · Structure of Atom
Calculate the mass of an elementary particle, which is accelerated to twice the velocity of light with the precision \(\pm 1 \%\) and has \(1.05 \times 10^{-13} \mathrm{~m}\) uncertainty in position. \(\left(h=6.6 \times 10^{-34} \mathrm{~kg} \mathrm{~m}^2 \mathrm{~s}^{-1}\right)\)
- A \(8.34 \times 10^{-27} \mathrm{~kg}\)
- B \(0.0083 \mathrm{~kg}\)
- C \(0.83 \times 10^{-27} \mathrm{~kg}\)
- D \(0.8 \times 10^{-28} \mathrm{~kg}\)
Answer & Solution
Correct Answer
(D) \(0.8 \times 10^{-28} \mathrm{~kg}\)
Step-by-step Solution
Detailed explanation
Precision \(= \pm 1 \%\) \(\therefore\) Accuracy \(=0.01\) \(\begin{aligned} & \Delta v=3 \times 10^8 \times \frac{2}{100}=6 \times 10^6 \mathrm{~m} / \mathrm{s} \\ & \Delta x=1.05 \times 10^{-13} \mathrm{~m}\end{aligned}\) We know that,…
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