AP EAMCET · Chemistry · Chemical Equilibrium
At \(\mathrm{T}(\mathrm{K}), \mathrm{K}_{\mathrm{c}}\) for the reaction. \(\mathrm{A}_2(\mathrm{~g}) \rightleftharpoons \mathrm{B}_2(\mathrm{~g})\) is 99.0 . Two moles of \(A_2(\mathrm{~g})\) was heated to \(T(K)\) in a \(1 L\) closed flask to reach the above equilibrium. What are the concentrations (in \(\mathrm{mol} \mathrm{L}^{-1}\) ) of \(\mathrm{A}_2(\mathrm{~g})\) and \(\mathrm{B}_2(\mathrm{~g})\) respectively at equilibrium?
- A \(1.86,0.0187\)
- B \(1.98,0.02\)
- C \(0.0187,1.86\)
- D \(0.02,1.98\)
Answer & Solution
Correct Answer
(D) \(0.02,1.98\)
Step-by-step Solution
Detailed explanation
given \(K_c=99.0\) \(\mathrm{n}=2\) moles of \(\mathrm{A}_2\) \(\mathrm{v}=1 \mathrm{~L}\)…
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