AP EAMCET · Chemistry · Solutions
At \(298 \mathrm{~K}\), the vapour pressure of a solution of \(7.5 \mathrm{~g}\) of non-volatile solute in \(90 \mathrm{~g}\) of water is \(2.8 \mathrm{kPa}\). If \(18 \mathrm{~g}\) of water is added to this solution the vapour pressure becomes \(2.81 \mathrm{kPa}\) at same temperature, the molar mass of solute in \(\mathrm{g} \mathrm{mol}^{-1}\) is
- A 17.5
- B 68.2
- C 71.5
- D 51.8
Answer & Solution
Correct Answer
(C) 71.5
Step-by-step Solution
Detailed explanation
Key Idea Relation between relative lowering of vapour pressure and molecular mass of solute is given by \(\frac{p^{\circ}-p}{p^{\circ}}=\frac{w_2 / M_2}{w_1 M_1}\) Given, Weight of non-volatile solute, \(w_2=7.5 \mathrm{~g}\) Weight of water, \(w_1=90 \mathrm{~g}\) Vapour…
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