AP EAMCET · Chemistry · Ionic Equilibrium
At \(25^{\circ} \mathrm{C}\), the percentage of ionization of \(x \mathrm{M}\) acetic acid is 4.242. What is the pH of the acetic acid solution?
\((\log 4.242=0.6275) ;(\log 0.04242=-1.372) \quad\left(\mathrm{K}_{\mathrm{a}}=1.8 \times 10^{-5}\right)\)
- A 3.37
- B 1.7
- C 1.37
- D 2.37
Answer & Solution
Correct Answer
(A) 3.37
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