AP EAMCET · Chemistry · Chemical Equilibrium
At \(1000 \mathrm{~K}\), the value of \(\mathrm{K}_{\mathrm{c}}\) for the below reaction is 10 \(\mathrm{mol} \mathrm{L}^{-1}\). Value of \(\mathrm{K}_{\mathrm{p}}\) (in atm) is
\(\mathrm{A}(\mathrm{g}) \rightleftharpoons \mathrm{B}(\mathrm{g})+\mathrm{C}(\mathrm{g})\)
(given \(\mathrm{R}=0.082 \mathrm{~atm} \mathrm{~L} \mathrm{~mol}{ }^{-1} \mathrm{~K}^{-1}\) )
- A \(82\)
- B \(0.82\)
- C \(8.2\)
- D \(820\)
Answer & Solution
Correct Answer
(D) \(820\)
Step-by-step Solution
Detailed explanation
\(K_p=K_c(R T)^{\Delta n_g}\)…
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