AP EAMCET · Chemistry · Chemical Bonding and Molecular Structure
Arrange \(\mathrm{O}_2, \mathrm{O}_2\left[A s \mathrm{~F}_6\right], \mathrm{KO}_2\) in the increasing order of bond length of \(\mathrm{O}-\mathrm{O}\) bond.
- A \(\mathrm{O}_2 < \mathrm{KO}_2 < \mathrm{O}_2\left[\mathrm{AsF}_6\right]\)
- B \(\mathrm{KO}_2 < \mathrm{O}_2 < \mathrm{O}_2\left[\mathrm{AsF}_6\right]\)
- C \(\mathrm{O}_2\left[\mathrm{AsF}_6\right] < \mathrm{KO}_2 < \mathrm{O}_2\)
- D \(\mathrm{O}_2\left[\mathrm{AsF}_6\right] < \mathrm{O}_2 < \mathrm{KO}_2\)
Answer & Solution
Correct Answer
(D) \(\mathrm{O}_2\left[\mathrm{AsF}_6\right] < \mathrm{O}_2 < \mathrm{KO}_2\)
Step-by-step Solution
Detailed explanation
Bond length \(\propto \frac{1}{\text { Bond order }}\) In \(\left.\mathrm{K}_2 \mathrm{O}_2\right)\) or \(\mathrm{O}_2^{-}\)bond order is 1.5 . In \(\mathrm{O}_2\) bond order is 2 . In \(\mathrm{O}_2\left(\mathrm{AsF}_6\right)\) or \(\mathrm{O}_2^{+}\)bond order is 2.5 . Hence,…
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