AP EAMCET · Chemistry · Structure of Atom
An element has \(d^5\) configuration. The total number of electron exchanges possible for it is
- A \(18\)
- B \(10\)
- C \(12\)
- D \(15\)
Answer & Solution
Correct Answer
(B) \(10\)
Step-by-step Solution
Detailed explanation
The total number of electron exchanges possibility is \(\frac{n(n-1)}{2}\) (where, \(n\) is the number of shells). By applying this formula for \(d^5\) configuration we get, \(=\frac{5(5-1)}{2}=\frac{5 \times 4}{2}=\frac{20}{2}=10\)
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