AP EAMCET · Chemistry · p Block Elements (Group 13 & 14)
Aluminium reacts with \(\mathrm{NaOH}\) and forms compound ' \(X\) '. If the coordination number of aluminium in ' \(X\) ' is 6 , the correct formula of \(X\) is
- A \(\left[\mathrm{Al}\left(\mathrm{H}_2 \mathrm{O}\right)_4(\mathrm{OH})_2\right]^{+}\)
- B \(\left[\mathrm{Al}\left(\mathrm{H}_2 \mathrm{O}\right)_3(\mathrm{OH})_3\right]\)
- C \(\left[\mathrm{Al}\left(\mathrm{H}_2 \mathrm{O}\right)_2(\mathrm{OH})_4\right]^{-}\)
- D \(\left[\mathrm{Al}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right](\mathrm{OH})_3\)
Answer & Solution
Correct Answer
(C) \(\left[\mathrm{Al}\left(\mathrm{H}_2 \mathrm{O}\right)_2(\mathrm{OH})_4\right]^{-}\)
Step-by-step Solution
Detailed explanation
\(2 \mathrm{Al}+2 \mathrm{NaOH}+2 \mathrm{H}_2 \mathrm{O} \longrightarrow \underset{\substack{\text { sodium } \\ \text { meta } \\ \text { aluminate }}}{2 \mathrm{NaAlO}_2}+3 \mathrm{H}_2\) Sodium metaaluminate, thus formed, is soluble in water and changes into the complex…
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