AP EAMCET · Chemistry · Some Basic Concepts of Chemistry
A flask contains 98 mg of \(\mathrm{H}_2 \mathrm{SO}_4\). If \(3.01 \times 10^{20}\) molecules of \(\mathrm{H}_2 \mathrm{SO}_4\) are removed from the flask, the number of moles of \(\mathrm{H}_2 \mathrm{SO}_4\) remained in flask is \(\left(\mathrm{N}=6.02 \times 10^{23}\right)\)
- A \(1 \times 10^{-4}\)
- B \(5 \times 10^{-4}\)
- C \(1.66 \times 10^{-4}\)
- D \(9.95 \times 10^{-3}\)
Answer & Solution
Correct Answer
(B) \(5 \times 10^{-4}\)
Step-by-step Solution
Detailed explanation
Weight of \(\mathrm{H}_2 \mathrm{SO}_4(W)=98 \mathrm{mg}\) \(=98 \times 10^{-3} \mathrm{~g}\left[1 \mathrm{mg}=10^{-3} \mathrm{~g}\right]\) No. of mole in flask \(\left(\mathrm{n}_1\right)=\frac{98 \times 10^{-3}}{98}=10^{-3}\) mole No. of mole removed from the flask…
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